The unsaturated imine (CH3)2C=CHC(CH3)=NC6H5 was found to react with (µ-H)2 83(CO )10 to produce the compounds (µ-H)2(µ3-n2-(CH3)2CHCC(CH3)=NC6H5)Os3(CO)9, A, and (µH)2 (µ3-n-4 CH2(CH3)CC(CH3)-NC6H5 O3 (CO)8 B. Both products have been characterized crystallographically by using diffractometer data. For A, the space group is P21/c (C2h), No. 14, with a = 14.818 (5) Å, b = 9.051 (5) Å, c = 20.098 (6) Å, s = 108.45 (3)° β, Z = 4, and pmlcd = 2.59 g/cm3. The structure was solved by the heavy-atom method and refined to the final residuals R1 = 0.058 and R2= 0.067. For B, the space group is P21/c, No. 14, with a = 16.060 (5) Å, b = 8.820 (4) Å, c = 16.809 (4)Å, β = 93.83 (2)², Z = 4, and pcalcd = 2.703 g/cm3. This structure was also solved by the heavy-atom method and refined to the final residuals R1 = 0.037 and R2= 0.041. A contains a µ-n2(CH3)2 CHCC(CH3)=NC6 H5 ligand bridging one face of a triangular cluster of osmium atoms. The nitrogen atom is terminally bonded to one osmium atom while the α-carbon serves as a bridge across the two remaining osmium atoms. The hydrogen atom on the carbon has been removed, and one has been added to the s-carbon, thus forming an isopropyl group. B contains a µ-3-n 4 CH 2 (CH3)— NC6H5 ligand bridging one face of a triangular cluster of osmium atoms. A terminally coordinated nitrogen atom is again bonded to one osmium atom. The -carbon bridges the two remaining osmium atoms. The α and β-carbon atoms have each lost one hydrogen atom. Together with the s-carbon atom they are bonded in the form of a π-allyl group to one osmiumatom. A has been independently converted into B through the dehydrogenation of the isopropyl group.
|Number of pages||7|
|State||Published - 1980|
ASJC Scopus subject areas
- Physical and Theoretical Chemistry
- Inorganic Chemistry